Castawords solutions    (back to main article and Puzzles)

(1)  AIJLTW BEFHOZ CNRSXY DGKMPU
(2)  ADGTVW BOPRXY CIKLMZ EFHNSU
(3)  ALMNWZ BCDIKS EFHOQR GPTUVY
(4)  AKNOUW BCDEHI FGMTXY JLPRSV
(5)  ABOPSZ CDFKUY
EGMNTX IJLRVW
(6)  ABJOWX CDELQV GMRSYZ HKNPTU
(7)  AFGOUX BCIPWY DMNSVZ HJKLQR
(8)  AFKNPT BHSUWX CIMORY DEGLQV
(9)  AGJPTV BHLSWZ DENORX FIMQUY
(10) ACSTWZ BIOQXY DFHJNR EGKLMU
(11) ABCIJO DHKRSV EMNPUX FGTWYZ
(12) ANPTVW BFLSUZ CEHKMY DGJORX
(13) ABCSUX DJOPTV EGKLMY FHINRW
(14) ACEGPT BDMOUV FHIJWY KLNQRS
(15) AMOSTV BEFGKY CDHPUZ ILNQRX
(16) ABFJOW CDIRUX EGHKSY LMNPTV


(17) HATE shares two letters in common with each of FACT and HAND, so none of them can be the red herring (nor can VOTE and WEST, though we don't need to know that).  If NECK is not the red herring, then we need to arrange the letters as CH / A / NT / DEF to allow for HATE, HAND, and FACT.  Then K must be with A to allow for NECK, making MARK the red herring.   So the red herring is either MARK or NECK, and we can add other words to two possible frameworks: CH / AKMR / NT / DEF (if MARK is the red herring) or FH / A / DT / CEKN (if NECK is the red herring).   The second group of the first framework (AKMR) already has four letters and needs either W or S from WEST, V or O from VOTE, and something from GILD, which would force it to have seven letters, which is impossible.  So NECK is the red herring and the second framework is correct.  Adding HYMN and MARK makes the framework FHR / AY / DMT / CEKN.   G must be with the first group to allow for both GILD and GAZE, giving us FGHR / AY / DMTZ / CEKN.   I must go with the second group to allow for JOIN, and O with the first to allow for VOTE, giving us FGHOR / AIVY / DJMTZ / CEKLN.  U must be with the third group to allow for BURY and PLUS, giving us FGHOR / AIVY / DJMTUZ / BCEKLN.  We still have to place W, S, and P in the first two groups to allow for WEST and PLUS.  The first group only has one spot left, so S must go there and W and P in the second group, giving the full solution in alphabetical order:

(17) AIPVWY BCEKLN DJMTUZ FGHORS

(18) AEGJMT BEHOPX COUVWY DKNSTZ FILQRS

(19) To start, assign the letters Y U K O N to five different blocks.  A and K cannot be on the same block (otherwise we could not spell DURAK); A also cannot be on the U or N blocks (JUNTA) or the O block (OWARE), so A is on the Y block.  R cannot be on the U, YA, or K block (DURAK), or the O block (PROBE), so R is on the N block, and we can assign D to the O block so that we can spell DURAK.  So far the blocks are AY / U / K / DO / NR.  I cannot be on YA (GIZA), U (QUBIC), K, or NR (RISK), so I is on DO. E must be on K (because of CLUE, REALM, PROBE), and W is on U to complete OWARE.  B must be on AY (PROBE and QUBIC), and P on UW completes PROBE.  Now the partially filled blocks are ABY / PUW / EK / DIO / NR.   L is on DIO (REALM and CLUE), and M on PUW completes REALM.  T is on EK (JUNTA and GHOST), and J on DILO completes JUNTA.  C is on NR (QUBIC and CLUE), and Q on EKT completes QUBIC.   CLUE forces one of the four blanks to be on ABY.    G must be on MPUW (FROG, GIZA, and GHOST), S on ABY (GHOST and RISK), and H on CNR, completing GHOST.  The blocks are now  ABSY* / GMPUW /  EKQT  /  DIJLO  /  CHNR (* indicating a blank).  There must also be a blank on UWPMG (RISK), which fills that block, so there is only room for the V in VIRA on EKQT.  Now EKQTV must contain a blank, since there is not room to put both F and Z to spell FROG and GIZA.  This fills that block, and the Z in GIZA must be on CHNR, and the F in FROG on ABSY*, filling that block.   The only place left for the X in HEX is on DIJLO, and the last blank is on CHNRZ.    The solution (in alphabetical order) is:

(19) ABFSY* CHNRZ* DIJLOX EKQTV* GMPUW*

(20) To start, assign the letters S H E E P to five different blocks. We also want to remember which four letters are repeated: A, E, L, and O.

I cannot be on the S block (SQUID) or the H or P block (APHID), so it is on one of the E blocks. R is not on the S or H block (SHREW), the EI block (TIGER), or the other E block (which must be the E in TIGER since the EI block will be used for I), so R is on the P block. C is not on the H block (CHIRO), the EI or E block (CIVET), or the P block (COYPU), so it is on the S block. T is not on the C, EI, E, or PR blocks (CIVET, TIGER), so it is on the H block, and we can finish CIVET and TIGER by placing V on the PR block and G on the CS block. We can also place one of the two Os on the E block to finish CHIRO. D goes on the EO block too (APHID, SQUID), and one of the two As goes on the SCG block to finish APHID. COYPU and SQUID force U to go on the HT block, and Q goes on the PRV block to finish SQUID. So far the blocks are ACGS / HTU / EI / DEO / PQRV.

Either F or N must go on the PQRV block (FINCH), but if it is F, there is only room for one more letter and we need two spots for L/A/M from LLAMA and B/O/N from BISON. So N must go there (with F going on the DEO block to finish FINCH), and we have only one spot left. Since we need a letter from both LLAMA and MOOSE, the sixth letter must be M. The second O then goes on the HTU block to finish MOOSE. Y goes on the EI block to finish COYPU. Since the ACGS block has one of the As, it cannot have an L (LLAMA), and thus must have the J from JUREL. The A there must be the A in QUAIL, so one of the Ls is on the DEFO block to finish QUAIL. The DEFLO block cannot have an A (LLAMA), so it has the X from HYRAX, which fills the block. Since there is no room on DEFLOX, the W in SHREW must be on the EIY block. Since the DEFLOX block is full, the O there must be the O in both BISON and OKAPI, so the HOTU block must have the B for BISON and either K or the second A for OKAPI. It cannot have K, since the block would then be full and have no room for any letters from LLAMA. So the block must be ABHOTU. The EIWY block must have the second L to finish LLAMA, as well as Z to finish ZEBRA (since the E in ZEBRA must be on the DEFLOX block). The K goes on the ACGJS block to finish OKAPI, and the puzzle is solved. The full solution (in alphabetical order) is:

(20) ABHOTU ACGJKS DEFLOX EILWYZ MNPQRV

(21) First we need to list all of the five letter words (including LOGIC which appears in the title -- sorry!).  There are thirteen:
BREAK  CHORD  LOGIC  LYRIC  MAJOR  MOTIF  POLKA   ROUND  SIXTH  SUITE  TWICE  VOICE  WALTZ 
[I confess that the puzzle contained a mistake when it was published in 2000 on the Games Cafe: it had the erroneous five-letter word which, written (by me) by mistake instead of that.]
We're going to use the second solving method described on the main page (as used to solve puzzle 2):
instead of starting with one letter on each block and adding letters one by one, we build one entire block at a time. Start with the block containing O (it's usually best to begin with one of the letters which appears most often in the word list).  What other letters are on this block? One of the letters must be from TWICE, but not from VOICE or MOTIF, so it is W.  One must be from BREAK, but not from MAJOR, POLKA, or VOICE, so it is B.  One is from SUITE, but not from MOTIF, ROUND, or VOICE, so it is S. One is from LYRIC, but not from CHORD, MOTIF, or POLKA, so the fifth letter is Y.  Already we have an entire block: BOSWY.   Next, the block containing I cannot contain any of the letters BOSWY, nor any of the letters from other words containing I.  One of the letters must be from CHORD, but not from LYRIC or SIXTH, so it is D.  From MAJOR we can use either A or J, but if we use A, we will find that there are too few letters left, since every word contains A, D, or I.  So we eliminate A and use J from MAJOR, and subsequently Z from WALTZ and K from BREAK.  That completes a second block: DIJKZ.   One advantage of this method is that it usually gets easier with each completed block.  The block containing R must also contain T from WALTZ, P from POLKA, V from VOICE, and G from LOGIC.   The last two blocks can be done at the same time, by starting with any word (e.g. BREAK) and putting the two remaining letters on different blocks: BOSWY/DIJKZ/GPRTV/E????/A????.  Then pick a word with either E or A (e.g. MAJOR), and add the fifth letter to the other block: BOSWY/DIJKZ/GPRTV/EM???/A????.   Using MOTIF, TWICE, and CHORD in succession gives us BOSWY/DIJKZ/GPRTV/EHM??/ACF??.    The remaining letters come from POLKA, SIXTH, SUITE, and finally ROUND. The full solution is:

(21) ACFUX  BOSWY  DIJKZ  EHLMN  GPRTV

(22) AFKOPY BENSUX CDJLMT HIRVWZ
(23) AUXZ** BHIKR* CDEFJY GMNQT* LOPSVW

(24) ABEHLU CDIMWY FGKOQZ JNPRST
(25) ACEGUW BIMTYZ DHKLOV FKNPRS
(26) ADGIJN BLMPSU CEHKTV FORWYZ    (JADING PLUMBS KVETCH FROWZY)
(27) ADOWYZ BCLNRS EFKMPU GHIJTV


In the ten-word non-ideal puzzle, since every word contains A, it should be obvious that the five missing letters FHOQW are on the block with A.  The rest of the problem is not very hard:

(28) AFHOQW BIJKNS CEPRUX DGLMTV

Most recently edited on May 9, 2017.   
This article is copyright 2017 by Michael Keller.  All rights reserved.